12.45

Moderators: Chem_Mod, Chem_Admin

RenuChepuru1L
Posts: 58
Joined: Thu Jul 27, 2017 3:00 am

12.45

Postby RenuChepuru1L » Fri Dec 08, 2017 7:50 pm

can someone break down this problem- what is the main takeaway? are they trying to say more bonds is connected to acidity/basicity strength

Emily Glaser 1F
Posts: 156
Joined: Thu Jul 27, 2017 3:01 am

Re: 12.45

Postby Emily Glaser 1F » Fri Dec 08, 2017 11:45 pm

YO YO YO RENU

Okay, so you are given the pa value of each other the compounds. But, these are bases so you need to change it to pKb by doing this: 14 - pKa, since pKa/pKb follows same mathematical relationship as pH/pOH.

So once you subtract everything, the values turn out to be.
Ammonia (4.74)
Methylamine (3.44)
Ethlyamine (3.19)
Aniline (9.37)

Now compare values; think of it like pOH, where the lower value of pOH/pKb means greater strength, just last pH.

Therefore, Aniline < Ammonia < Methlyamine < Ethlyamine

<3


Return to “Calculating pH or pOH for Strong & Weak Acids & Bases”

Who is online

Users browsing this forum: No registered users and 2 guests