Relationship between pH, protanation and molarity

[Silvino Jimenez 1A]

Hi


How can pH or pOH be found
given % protonation/deprotanation and molarity?



Ty!

[Katie Lam 1B]

You use the molarity of H30+ and OH- to find the pH and pOH by taking the -log of each.
-log[H30+]=pH
-log[OH-]=pOH

[Rachel Formaker 1E]

For an acid, when given the initial molarity and percent deprotonation, you multiply the initial molarity by the percent deprotonation (as a decimal, so over 100) to find the concentration of H₃O⁺ ions in solution.
You then use this concentration to find pH in the normal way (pH=-log[H₃O⁺])

For bases, you do the same thing except for OH^- ions and pOH

[Eruchi Okpara 2E]

When solving for the percent deprotonation, is it always going to be the value you got for X (from the ICE table) divided by the initial concentration given?

[Eruchi Okpara 2E]

Can deprotonation still be found if we are given initial concentrations for both the reactants and products?

[Max Hayama 4K]

Yes! All you need to do is divide the equilibrium concentration of the conjugate acid/base by the initial concentration of the corresponding acid and base.