pH of strong acid-strong base reaction

[Chem_Mod]

Question: Hello, one of the homework problems asks "Sketch the titration of 5.00mL .010M NaOH with .005M HCl indicating the pH of the intial and final solution". How do you calculate the pH of the final solution? Do you simply take the -log of .005? Thank you!

[Chem_Mod]

Answer: Do you simply take the -log of .005? No. You should first calculate the concentration of [] and [] in the final solution, and then get the pH. Since you are dealing with strong acid and strong base titration, this problem becomes very simple. You just need to figure out the final concentration of NaOH and HCl after the neutralization reation NaOH + HCl NaCl +
.