6B. 5

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Gisela F Ramirez 2H
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Joined: Fri Sep 28, 2018 12:27 am

6B. 5

Postby Gisela F Ramirez 2H » Thu Dec 06, 2018 1:17 am

c.) 0.0092M Ba(OH)2

How do we calculate the pOH? And the pH?

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Re: 6B. 5

Postby Chem_Mod » Thu Dec 06, 2018 1:26 pm

You must first find the concentration of OH. For every 1 mole of Ba(OH)2, we have 2 moles of OH. Therefore the concentration of OH is double that of Ba(OH)2.

You can find the pOH by taking -log[OH-].
The pH and pOH must add up to 14, so you can deduce the pH from that.


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