Calculating pH
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Re: Calculating pH
You will need to know the molarity of the NaOH. Let's assume the solution is 0.1M. NaOH is a strong base, so this will produce 0.1mol/L of OH ions in solution. This will produce a pH of 13.
You will need to take the negative log of 0.1 to find the pOH. This will work out to be 1.
Since pH + pOH = 14
We can calculate the pH to be 13.
This assumption can only be used for strong bases which dissociate completely in water.
You will need to take the negative log of 0.1 to find the pOH. This will work out to be 1.
Since pH + pOH = 14
We can calculate the pH to be 13.
This assumption can only be used for strong bases which dissociate completely in water.
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- Posts: 64
- Joined: Fri Sep 28, 2018 12:24 am
Re: Calculating pH
For example, we are given that the molarity of a solution is 0.1M NaOH. Since we know that NaOH is a strong base, we know that it will fully dissociate. Therefore,
0.1 M NaOH --> 0.1 M OH-
pH = 14 - pOH = 14 - (-log([OH-])) = 14 - (-log([0.1M)) = 14 - 1 = 13
So, the final answer is pH = 13.
0.1 M NaOH --> 0.1 M OH-
pH = 14 - pOH = 14 - (-log([OH-])) = 14 - (-log([0.1M)) = 14 - 1 = 13
So, the final answer is pH = 13.
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