Question 6B3

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Cecilia Jardon 1I
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Joined: Fri Sep 28, 2018 12:16 am

Question 6B3

Postby Cecilia Jardon 1I » Sat Dec 08, 2018 8:33 pm

A careless laboratory technician wants to prepare 200.0 ml of a 0.0025 M HCl (aq) solution but uses a volumetric flask of volume 250.0 mL by mistake. What will be the actual pH of the solution.
On the solutions manual it says that the answer is -log(200.00ml x 0.0025 M/ 250.0) which equals 1.7. I do not understand why we would have to multiply 200.00 ml to 0.0025M. Can someone explain.

bonnie_schmitz_1F
Posts: 81
Joined: Fri Sep 28, 2018 12:24 am
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Re: Question 6B3

Postby bonnie_schmitz_1F » Sat Dec 08, 2018 10:31 pm

The number inside the parentheses is the new molarity that they found using the eqautions: (MinitialVinitial)/Vfinal = Mfinal.


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