6th edition #12.19  [ENDORSED]

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Hannah Morales 1D
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6th edition #12.19

Postby Hannah Morales 1D » Sun Dec 09, 2018 2:55 am

The concentration of HCl in hydrochloric acid is reduced to 12% of its initial value by dilution. What is the difference in the pH values of the two solutions?

In the solutions manual it has

DeltapH = -log(.12[HCl]/[HCl])
How do you know as to cancel out HCl as shown above?

Chem_Mod
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Re: 6th edition #12.19  [ENDORSED]

Postby Chem_Mod » Sun Dec 09, 2018 9:38 am

If you think about it, let's say the molarity of the initial HCl is 3M. If the final molarity is reduced to 12% of its initial, it will be 3M(.12).

(0.12)(3)=(3)

Therefore, you can cancel out the 3's.


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