7th Edition 6B.9

Moderators: Chem_Mod, Chem_Admin

Kathryn Wilhem 1I
Posts: 48
Joined: Thu Sep 27, 2018 11:27 pm

7th Edition 6B.9

Postby Kathryn Wilhem 1I » Wed Jan 16, 2019 8:51 pm

For parts (i) and (ii) of the problem, we are given the [H30+] = 1.50M and [OH-] = 1.50M respectively. When I calculated the pH and pOH, I found that the answer was -0.176. When we know that taking the log of the concentration will give us a positive answer, do we just not put a negative sign in front of it?

Posts: 16494
Joined: Thu Aug 04, 2011 12:53 pm
Has upvoted: 349 times

Re: 7th Edition 6B.9

Postby Chem_Mod » Thu Jan 17, 2019 1:52 pm

pH =-log[H3O+], if you plug in the 1.5, you should get about 0.176

Return to “Calculating pH or pOH for Strong & Weak Acids & Bases”

Who is online

Users browsing this forum: No registered users and 1 guest