6B.9

Moderators: Chem_Mod, Chem_Admin

Nicole Garrido 2I
Posts: 52
Joined: Fri Sep 28, 2018 12:18 am

6B.9

Postby Nicole Garrido 2I » Sat Mar 16, 2019 1:32 pm

I don't understand the solutions in the solution manual for this question. Why can't I divide Kw by the conc. of H3O+ to find OH-. Also, when I take the -log of the H3O+ conc it gives me a negative of the actual solution.

keyaluo4C
Posts: 54
Joined: Fri Sep 28, 2018 12:17 am

Re: 6B.9

Postby keyaluo4C » Sat Mar 16, 2019 4:27 pm

You should be able to divide Kw by the concentration of H3O+ to get the same solution for the concentration of OH-. For (i) in the table you get a negative as the answer for pH but that should also be the correct pH. pH for (i) = -0.176.


Return to “Calculating pH or pOH for Strong & Weak Acids & Bases”

Who is online

Users browsing this forum: No registered users and 1 guest