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Nicole Garrido 2I
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Joined: Fri Sep 28, 2018 12:18 am


Postby Nicole Garrido 2I » Sat Mar 16, 2019 1:32 pm

I don't understand the solutions in the solution manual for this question. Why can't I divide Kw by the conc. of H3O+ to find OH-. Also, when I take the -log of the H3O+ conc it gives me a negative of the actual solution.

Posts: 54
Joined: Fri Sep 28, 2018 12:17 am

Re: 6B.9

Postby keyaluo4C » Sat Mar 16, 2019 4:27 pm

You should be able to divide Kw by the concentration of H3O+ to get the same solution for the concentration of OH-. For (i) in the table you get a negative as the answer for pH but that should also be the correct pH. pH for (i) = -0.176.

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