6B.9
Posted: Sat Mar 16, 2019 1:32 pm
by Nicole Garrido 2I
I don't understand the solutions in the solution manual for this question. Why can't I divide Kw by the conc. of H3O+ to find OH-. Also, when I take the -log of the H3O+ conc it gives me a negative of the actual solution.
Re: 6B.9
Posted: Sat Mar 16, 2019 4:27 pm
by keyaluo4C
You should be able to divide Kw by the concentration of H3O+ to get the same solution for the concentration of OH-. For (i) in the table you get a negative as the answer for pH but that should also be the correct pH. pH for (i) = -0.176.