6B.1

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Joanne Kang 3I
Posts: 50
Joined: Thu Jul 25, 2019 12:17 am

6B.1

Postby Joanne Kang 3I » Fri Nov 29, 2019 10:32 pm

1. The molar concentration of HCl in hydrochloric acid is reduced to 12% of its initial value by dilution. What is the difference in the pH values of the two solutions?
Can someone please explain the solution for this question?

Kayli Choy 2F
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am

Re: 6B.1

Postby Kayli Choy 2F » Sat Nov 30, 2019 10:53 am

In this problem, you are finding the change in pH values so you could set up the equation:
(change in pH) = -log(1) - (-log(.12))

You are using 1 and .12 because the HCl is reduced to only 12% of its initial value.

Hope this helps!


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