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pH calcuations

Posted: Sun Dec 01, 2019 6:00 pm
by kpang_4H
Are pH=-log(H+) and pH=-log(OH-) the only equations we need to know, regarding pH, for the final?

Re: pH calcuations

Posted: Sun Dec 01, 2019 6:05 pm
by Samuel Tzeng 1B
I believe so

Re: pH calcuations

Posted: Sun Dec 01, 2019 6:05 pm
by JonathanS 1H
Other than molarity calculations we did ad the beginning of the quarter, we have not done any other calculations with pH besides the ones you have mentions, so I assume so.

Re: pH calcuations

Posted: Sun Dec 01, 2019 7:31 pm
by Bradley Whitworth 4B
Regarding concentrations and the equations related to acid/base reactions I imagine we'll probably have to know those equations about Kb and Ka.

Re: pH calcuations

Posted: Sun Dec 01, 2019 8:09 pm
by IScarvie 1E
So far, yes

Re: pH calcuations

Posted: Mon Dec 02, 2019 8:36 am
by MBouwman_4A
It may also be helpful to remember that pH + pOH = 14.

Re: pH calcuations

Posted: Mon Dec 02, 2019 8:47 am
by Callum Guo 1H
I think so, unless he gives us another one

Re: pH calcuations

Posted: Mon Dec 02, 2019 8:55 am
by preyasikumar_2L
That and pH+pOH=14, and perhaps equations relating to Ka.

Re: pH calcuations

Posted: Mon Dec 02, 2019 9:16 am
by DMuth_1J
Just to clarify, I think it's a typo, but pH= -log(H+) and pOH= -log(OH-). Make sure the pH is associated with the H+ / H3O+ and the pOH is associated with the OH-