6B.9 Row 2&1

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Jessica Esparza 2H
Posts: 130
Joined: Wed Sep 18, 2019 12:15 am

6B.9 Row 2&1

Postby Jessica Esparza 2H » Tue Dec 03, 2019 10:52 am

6B.9 asks you to find the missing values given only certain ones. On row 1 they give you a H30+ concentration of 1.5, you can find the ph to be .176. However, when I would try to get the [H30+] concentration through the pH to double check my answers I would not get 1.5 through the equation we're supposed to use ([H30+]= 10^-ph. Instead I had to use the postive pH. For example, to get 1.5 from a .176 ph, I used 10^+pH. Why would we not use the negative ph in this case?

Maia_Jackson_2C
Posts: 101
Joined: Fri Aug 30, 2019 12:17 am

Re: 6B.9 Row 2&1

Postby Maia_Jackson_2C » Tue Dec 03, 2019 2:15 pm

In row 1 the pH of H30+ with 1.5M is -0.176, so when you do ([H30+]= 10^-pH, it looks like, ([H30+]= 10^-(-0.176)=1.5M. The negative signs cancel out so the equation does work, even though the pH is negative.

Jessica Esparza 2H
Posts: 130
Joined: Wed Sep 18, 2019 12:15 am

Re: 6B.9 Row 2&1

Postby Jessica Esparza 2H » Tue Dec 03, 2019 4:13 pm

Ah I see that makes sense!


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