help with 6B.9

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Brian Tangsombatvisit 1C
Posts: 108
Joined: Sat Aug 17, 2019 12:15 am

help with 6B.9

Postby Brian Tangsombatvisit 1C » Wed Dec 04, 2019 8:17 pm

I tried using the relationships pH= -log[H3O+], [H3O+][OH-]= 1.0x10^-14, etc, but I can't seem to get the right values for filling out the table.

Mashkinadze_1D
Posts: 87
Joined: Sat Aug 24, 2019 12:15 am

Re: help with 6B.9

Postby Mashkinadze_1D » Wed Dec 04, 2019 9:05 pm

If you are referring to the right tables, in the solutions book I kept getting these wrong too. I believe there may be an error for when I multiplied their concentrations I did not get 1 x 10^-14 and the product of [H30+] times [OH-] should be this.

Hannah Lee 2F
Posts: 99
Joined: Thu Jul 11, 2019 12:15 am

Re: help with 6B.9

Postby Hannah Lee 2F » Thu Dec 05, 2019 8:07 pm

I also kept on getting answers different from the solutions manual, so the manual itself may be incorrect. It's not on Dr. Lavelle's list of 7th Ed Solution Manual errors though, so I'm not sure. I used the relationship pH = -log[H+] and [H+] x [OH-] = 1.0 x 10^-14 to get the following answers for (i):
[H+] = 1.50 M
[OH-] = 6.67 x 10^-5 M
pH = -0.176
pOH = 14.176
but please correct me if I'm doing something wrong!


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