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help with 6B.9

Posted: Wed Dec 04, 2019 8:17 pm
by Brian Tangsombatvisit 1C
I tried using the relationships pH= -log[H3O+], [H3O+][OH-]= 1.0x10^-14, etc, but I can't seem to get the right values for filling out the table.

Re: help with 6B.9

Posted: Wed Dec 04, 2019 9:05 pm
by Mashkinadze_1D
If you are referring to the right tables, in the solutions book I kept getting these wrong too. I believe there may be an error for when I multiplied their concentrations I did not get 1 x 10^-14 and the product of [H30+] times [OH-] should be this.

Re: help with 6B.9

Posted: Thu Dec 05, 2019 8:07 pm
by Hannah Lee 2F
I also kept on getting answers different from the solutions manual, so the manual itself may be incorrect. It's not on Dr. Lavelle's list of 7th Ed Solution Manual errors though, so I'm not sure. I used the relationship pH = -log[H+] and [H+] x [OH-] = 1.0 x 10^-14 to get the following answers for (i):
[H+] = 1.50 M
[OH-] = 6.67 x 10^-5 M
pH = -0.176
pOH = 14.176
but please correct me if I'm doing something wrong!