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This is a strong acid/strong base reaction, so you need to determine whether the resulting solution has an excess hydronium or hydroxide through dimensional analysis with the balanced equations in water. It turns out there is more hydronium and pH=-log[H+]= 2.28.
he most important part of this problem is remembering that CaO, a strong base, produces 2 moles of OH-. Convert these masses of HCl and CaO into moles of H+ and OH- respectively. It is basically like a limiting reactant problem, so whichever produces more H+ or OH- is in excess, and we want to find how much H+ or OH- is in excess. So, subtract the two values you got for the moles of OH- and H+ and divide that difference by the liters given, in this case it is 1 so doesn't matter but it will if the volume is anything other than 1. Then, you can plug this molarity into the pH (if H+ is in excess) to find pH, or pOH (if OH- is in excess) and subtract this from 14 to get pH.
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