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Ashley Kao 1H
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Joined: Thu Jul 25, 2019 12:16 am


Postby Ashley Kao 1H » Sat Dec 07, 2019 12:56 pm

In 6B.1, we are asked to find the difference in pH of a HCl solution if it is diluted by 12% of the initial molar concentration. How do we solve this if we are not given the initial molar concentration or pH?

Jacob Puchalski 1G
Posts: 97
Joined: Fri Aug 09, 2019 12:16 am

Re: 6B.1

Postby Jacob Puchalski 1G » Sat Dec 07, 2019 1:58 pm

The pH scale is a log scale, so if you reduce the molar concentration to .1, or 10% of the original concentration then the resulting pH will raise by 1; -Log(.1) = 1. So if molarity of HCl is reduced to 12% of the original concentration, then -log(.12) = .92. So all you need to know is the difference between the new and old pH is +.92, or the pH rose by .92.

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