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Textbook question 6B.9

Posted: Wed Jan 15, 2020 3:21 pm
by Paige Lee 1A
Could someone please explain how to fill in the table for solutions 1 and 2?
I got that the concentrations were 1.50mol/L and 6.67*10^-15
I got that the pHs and pOHs for these two solutions were -0.18 and 14.18

Re: Textbook question 6B.9

Posted: Wed Jan 15, 2020 3:31 pm
by Veronica_Lubera_2A
I think that for when calculating pH, you can drop the negative in the final answer to get 0.18 pH from 1.5 M H3O+ instead of -0.18 M.
So from that you get pOH by doing 14-0.18=13.824.
And the concentration of OH- is 10^-13.824 which equal 1.5*10^-14.