Textbook question 6B.11

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Paige Lee 1A
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Joined: Sat Sep 07, 2019 12:16 am

Textbook question 6B.11

Postby Paige Lee 1A » Wed Jan 15, 2020 3:38 pm

Could someone please explain how to get the answers to parts a.ii and b?
I understand how to get part a.i

005391550
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Joined: Thu Jul 25, 2019 12:15 am

Re: Textbook question 6B.11

Postby 005391550 » Wed Jan 15, 2020 3:42 pm

In order to find the original solution's concentration of OH-, use the diluted concentration that you found in part ai) and find how many mols of OH- are really in the diluted solution. Then use this number of mols of OH- and divide it by 5.00mL to find the original concentration. This works because the number of moles in dilutions will not change.

005391550
Posts: 92
Joined: Thu Jul 25, 2019 12:15 am

Re: Textbook question 6B.11

Postby 005391550 » Wed Jan 15, 2020 3:45 pm

for part b, you want to use the concentration of the original solution (answer to part aii) which is the concentration of OH- of the original solution. Using this information, you can use the OH- concentration to find the mols of OH- in that 200mL solution. using the mols of OH-, you can convert it into mols of NaOH and then Na2O and then convert to grams


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