6D.15

Moderators: Chem_Mod, Chem_Admin

Riya Sood 4G
Posts: 133
Joined: Sat Aug 24, 2019 12:18 am

6D.15

Postby Riya Sood 4G » Wed Jan 15, 2020 11:22 pm

Calculate the pH of (a) 0.19 m NH4Cl(aq); (b) 0.055 m
AlCl3(aq).

How do we do part b of this question? What will be the dissociation reaction?

Selena Yu 1H
Posts: 98
Joined: Fri Aug 09, 2019 12:16 am

Re: 6D.15

Postby Selena Yu 1H » Thu Jan 16, 2020 12:27 am

The dissociation reaction is AlCl3 + H2O --> Al(OH)3 + HCl. H2O would always be added because it is a solvent and then with that you could figure out the products. The equation above is not balanced and then HCl would dissolve into H+ and Cl- and you would use that to calculate the pH.


Return to “Calculating pH or pOH for Strong & Weak Acids & Bases”

Who is online

Users browsing this forum: No registered users and 1 guest