6B.9

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Tiffany Chao 2H
Posts: 117
Joined: Fri Aug 09, 2019 12:17 am

6B.9

Postby Tiffany Chao 2H » Thu Jan 16, 2020 4:49 pm

For 6B.9 i and ii, I keep getting different answers from the answer key. For i), I do the negative log of 1.50 and get the pH to be -0.176, [OH-] to be 6.67x10^-15, and pOH to be 14.17. This doesn't match the textbook that says pH = 0.176, [OH-] = 1.50x10^-14, and pOH = 13.824. I just don't know what I'm doing wrong.
Thanks

Luyan Zhang - 2D
Posts: 103
Joined: Sat Jul 20, 2019 12:16 am

Re: 6B.9

Postby Luyan Zhang - 2D » Thu Jan 16, 2020 10:13 pm

Me too! I think the solution manual is wrong. Because taking the negative log of a number greater than one is negative. But the solution has a positive pH

Minh Ngo 4G
Posts: 137
Joined: Thu Jul 25, 2019 12:17 am

Re: 6B.9

Postby Minh Ngo 4G » Fri Jan 17, 2020 12:16 am

I didnt get the same ans as the back of the textbook either! For i i got -0.176 for pH instead of 0.176. There's probably a typo somewhere (??!), I hope

Alondra
Posts: 36
Joined: Tue Feb 26, 2019 12:15 am

Re: 6B.9

Postby Alondra » Mon Jan 20, 2020 1:20 am

I think on the class website there's a sheet about some errors in the solution manual. Not so sure though.


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