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Andrew Pfeiffer 2E
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Joined: Sat Sep 28, 2019 12:16 am


Postby Andrew Pfeiffer 2E » Sun Jan 19, 2020 4:20 pm

Does anyone know how to do 5I.33? Thanks y'all.

JonathanS 1H
Posts: 101
Joined: Thu Jul 11, 2019 12:17 am

Re: 5I.33

Postby JonathanS 1H » Sun Jan 19, 2020 7:06 pm

To start off, you want to change all gram measurements into moles by dividing by the grams/mole of each substance because we are dealing with equilibrium. From the equation, we know that 2 moles of NH3 are formed per mole of CO2 formed, so we multiply our moles of CO2 by 2 to get our moles of NH3 formed. Next, we divide each by the Liters to get molarity. Finally, we use the molarities to calculate the KC for the reaction, excluding any liquids and solids.

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