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5I.33

Posted: Sun Jan 19, 2020 4:20 pm
by Andrew Pfeiffer 2E
Does anyone know how to do 5I.33? Thanks y'all.

Re: 5I.33

Posted: Sun Jan 19, 2020 7:06 pm
by JonathanS 1H
To start off, you want to change all gram measurements into moles by dividing by the grams/mole of each substance because we are dealing with equilibrium. From the equation, we know that 2 moles of NH3 are formed per mole of CO2 formed, so we multiply our moles of CO2 by 2 to get our moles of NH3 formed. Next, we divide each by the Liters to get molarity. Finally, we use the molarities to calculate the KC for the reaction, excluding any liquids and solids.