pH to pOH
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pH to pOH
When given the pH of a solution, to get to the pOH I have been subtracting the pH from 14, and doing the same thing for going from pOH to pH. Is this the right method, and if so, why?
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Re: pH to pOH
Yes, this is correct. This is because the concentration of pH times the concentration of POH must equal to to the equilibrium constant for the ionization of water, which is 1.0 x 10^-14. If you take the log of both sides and simplify, you would get pH + pOH =14.
We use pH and pOH because representing the concentration in whole numbers is easier that always saying the concentration of H= is 2.3 x 10^-6 (which equals pH of 5.6) or something like that.
We use pH and pOH because representing the concentration in whole numbers is easier that always saying the concentration of H= is 2.3 x 10^-6 (which equals pH of 5.6) or something like that.
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Re: pH to pOH
I agree with the answer above in regards to the original question. pOH is basically pH (ie -log[H+]) but instead of focusing on H+ concentration, we focus on OH- concentration. So pH and pOH are complimentary in that way, and always add up to 14.
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Re: pH to pOH
Heather Szeszulski 1I wrote:what is pOH? i am a little confused
pOH is a measure of the concentration of the hydroxide ion [OH-].
Just know that [OH-}*[H+]=1.00*10^-14, and pOH+pH=14.00
Here is a site that explains it in more detail: https://courses.lumenlearning.com/chemi ... h-concept/
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Re: pH to pOH
Yes, just know that pH+pOH= 14, so you can rearrange the equation depending on what is given.
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Re: pH to pOH
Also make sure given any of the four components (pH, pOH, OH- levels, H+ levels) that you can get the other three, as seen in the Sapling homework for this week.
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Re: pH to pOH
OwenSumter_3D wrote:Also make sure given any of the four components (pH, pOH, OH- levels, H+ levels) that you can get the other three, as seen in the Sapling homework for this week.
What do you mean by OH- and H+ levels? I haven't started the homework yet, but I'm assuming this means the concentration of H30+ and OH-? With those values, you would simply plug both into -log base 10 to get pH and pOH, respectively. If I'm wrong, could someone explain how to utilize these two values?
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Re: pH to pOH
yea, just know that 14 = pH + pOH. Also, to find [H+] from pH, the equation is [H+] = 10^-pH, and for [OH-], [OH-] = 10^-pOH
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