Textbook 6D.5

Moderators: Chem_Mod, Chem_Admin

Gwendolyn Hill 2F
Posts: 111
Joined: Wed Sep 30, 2020 9:39 pm
Been upvoted: 3 times

Textbook 6D.5

Postby Gwendolyn Hill 2F » Sat Jan 23, 2021 4:38 pm

Hi!
So the problem is as follows:
6D.5 Calculate the pH, pOH, and percentage protonation of sol- ute in each of the following aqueous solutions: (a) 0.057 m NH3(aq); (b) 0.162 m NH2OH(aq); (c) 0.35 m (CH3)3N(aq); (d) 0.0073 m codeine, given that the pKa of its conjugate acid is 8.21.

On part a, in the solutions it says Kb = 1.8 x 10^-5, and that's how you solve for x. I am confused on how that is the Kb value? How would we find the Kb value..? Are we supposed to use the table from before in the book?

Peter DePaul 1E
Posts: 101
Joined: Wed Sep 30, 2020 9:55 pm
Been upvoted: 1 time

Re: Textbook 6D.5

Postby Peter DePaul 1E » Sat Jan 23, 2021 5:00 pm

Yeah you would have to find the value from the textbook and whatever value they provide is the one to use.

Gwendolyn Hill 2F
Posts: 111
Joined: Wed Sep 30, 2020 9:39 pm
Been upvoted: 3 times

Re: Textbook 6D.5

Postby Gwendolyn Hill 2F » Sat Jan 23, 2021 5:06 pm

Peter DePaul 1E wrote:Yeah you would have to find the value from the textbook and whatever value they provide is the one to use.

Thanks!


Return to “Calculating pH or pOH for Strong & Weak Acids & Bases”

Who is online

Users browsing this forum: No registered users and 4 guests