### Writing Molarity of IONS as Logarithms: Solving Logarithms

Posted:

**Thu Nov 19, 2015 11:13 pm**In the Chemistry 14a Course Reader on page 139, Lavelle has written:

" -log(1.7 * 10^(-12)) = -(-11.8) = 12 "

I am confused how he got to the value -11.8 from the equation -log(1.7 * 10^(-12)).

Could someone please explain to me how to solve this logarithm (along with logarithms in general) step by step? Thank you.

" -log(1.7 * 10^(-12)) = -(-11.8) = 12 "

I am confused how he got to the value -11.8 from the equation -log(1.7 * 10^(-12)).

Could someone please explain to me how to solve this logarithm (along with logarithms in general) step by step? Thank you.