Achieve Week 10 #5

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Bailey Wallace 3A
Posts: 52
Joined: Fri Sep 24, 2021 6:15 am

Achieve Week 10 #5

Postby Bailey Wallace 3A » Tue Nov 30, 2021 12:28 am

Determine the [H+], [OH−], and pOH of a solution with a pH of 3.51 at 25 °C.

I was able to calculate the pOH but I am having a hard time with the [H+] and [OH−], can anyone help me?

Ashley M 2E
Posts: 105
Joined: Fri Sep 24, 2021 6:45 am

Re: Achieve Week 10 #5

Postby Ashley M 2E » Tue Nov 30, 2021 10:38 am

To find [H+] and [OH-], use the equation pH=-log[H+] and pOH=-log[OH-]. To undo the log, you basically take 10^-pH and 10^-pOH to find your answer.

Holland Smith 3C
Posts: 83
Joined: Fri Sep 24, 2021 6:12 am

Re: Achieve Week 10 #5

Postby Holland Smith 3C » Tue Nov 30, 2021 11:41 am

I am also having trouble with this problem. I was able to find the pH, but how to I find the [OH-] value to plug into the log equation?

Tyler_Kim_2G
Posts: 105
Joined: Fri Sep 24, 2021 6:50 am

Re: Achieve Week 10 #5

Postby Tyler_Kim_2G » Tue Nov 30, 2021 12:09 pm

Hey Holland, if you know the [H+] value, you could determine the [OH-] value by the relationship [OH-]=(1.0 x 10^-14)/[H+]. If you do not already know the [H+], you can use the pH value and undo the log by using the relationship stated above.


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