Achieve textbook question 6B.5
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Achieve textbook question 6B.5
For this question, how do you come up with the pH and pOH? How come it is different from a) and b). can we not use -log(0.0092)?
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Matthew Li 1B
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- Joined: Fri Sep 24, 2021 6:40 am
Re: Achieve textbook question 6B.5
-log(0.0092) would be calculating the pOH as the molecule is a subject. after finding out the pOH we would use 14 - pOH to find the pH
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