How to Calculate OH- Concentration

[Alyssa Gutierrez 3A]

Hi, how do I calculate the OH- concentration given the H+ concentration as in question 5 in the Achieve homework?

[Sanjana Narayanan 2J]

We know that the product of the H+ and OH- concentration is 10^-14, so given the H+ concentration, you can divide 10^-14 by the H+ concentration to find the OH- concentration.

[Matthew Nguyen 2F]

This is a bit of lengthy method but how I did it was I subtracted the pH from 14; this gives the pOH value with which you can then use to calculate the concentration of OH- ions through the formula pOH = -log([OH-]), which you would rearrange to [OH-] = antilog(-pOH).

[Lauren Brotman 2F]

There are different ways you could. The fastest would probably be using 1.0×10−14=[H+][OH−]. Plug in H+ concentration to solve for OH- concatenation.

Another way would be first use H+ concentration to calculate pH with pH=−log[H+], then 14-pH to fine pOH, then do 10^-pOH to find OH- concentration. This might a good way if the problem also asks for pH and pOH.

[Ginny Ghang 1B]

If given [H+], the fastest way to find [OH-] would be to use the equation: 1.0x10^-14 = [H+][OH-].
The other way to solve this is to use: 14 = pH + pOH, pH = -log[H+], pOH = -log[OH-]. With the given [OH-], find pOH. Then, use 14 = pH + pOH to find pH. Take this pH and plug into pH = -log[H+]. Solve, 10^-pH to get [H+].

[Lindsey Walter 3E]

To find the [OH-] given [H+], use 1.0 x 10^-14 = ([OH-])([H+]). This means that is you have the [H+], you just need to divide it by 1.0 x 10^-14 to get [OH-].

[Bela Patel 2B]

In order to determine the [OH-] from [H+], you would need to divide [H+] by 1*10^-14.

[daniellediem1k]

(10^-14) / [H+] = [OH-]

[HaleyC 2F]

Use the equation 1.0 x 10^-14 = ([OH-])([H+]). First you isolate [OH-] and then plug the [H+] in the equation.

[madeleinewright]

To find the OH- concentration given the H+ concentration, you can use the equation 1.0x10^-14/[H+].

[Julia Todorov 2F]

the product of [OH-] and [H+] are 10^-14, so you can divide 10^-14 by [OH-] to find [H+] and vice versa

[Denise Chavez 2G]

Once you know the [H+] concentration you should be able to find the [OH-] concentration since the equation for the [OH-] concentration is 1.0 x 10^-14 / [H+].

[Eszter Kovacs 1A]

You can calculate the pH from H+ concentration. pOH=14-pH, so you can calculate the pOH and from that the concentration of OH-.

[Marilyn]

pOH=log[OH-]
[OH-]=10^pH

[Divya Mehta 2K]

The product of the H+ and OH- concentration =10^-14, so if you have the H+ concentration, you can divide 10^-14 by the H+ concentration to find the OH- concentration.

[Hope Galarneau 1A]

the product of the OH- and H+ concentration are equal to Kw, which is 10^-4. Thus, if you have one of the concentrations, you can divide it by Kw to find the other. Additionally, you could also find the pH or pOH and then use the 10^-pH to find the concentration.

[Daniela G 2C]

When given H+, first find pH with the equation pH = -log[H+]. Then find pOH with the equation pOH = 14 - pH. Finally, you can find OH- with the equation [OH-] = 10^-pOH.

[Kelly_Luong_1F]

Using the relationship [OH-][H+] = 1.0 x 10^-14, plugging in the [H+] and then simplifying would allow you to calculate the [OH-].

[405566265]

the feedback of the solution gives you helpful formulas to use!