6B.5

[Anna Castaneda 2E]

Calculate the pH and pOH of each of the following aqueous solutions of a strong acid or base: (c) 0.0092M Ba(OH)2 (aq)

Could anyone explain how they solved part C?

[Elsie_Lin_2K]

You would have to multiply the molar concentration by two due to the chemical formula Ba(OH)2. After multiplying it, you would take the negative log and that would give you the pOH which is 1.74. You could subtract 1.74 from 14 to find the pH of the solution.

[Jonathan Sautter 1J]

You could also begin by dividing (1 x 10^-14)/(.0092) and then divide that answer by 2 to get 5.43. And then you could take the -log of this number to get the pH= 12.26. Subtracting this from 14 will give you the pOH= 1.74. Both of these ways work, but I definitely think that Elsie's way is a lot easier and more straight forward.