pH v.pOH
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Re: pH v.pOH
Calculating pH is done by taking the -log of the H3O+ concentration while the pOH is calculated by taking the -log of the OH- concentration. To find the other, subtract that number from 14. For example, if you solved for pOH, calculate 14-pOH to find pH.
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Re: pH v.pOH
pH + pOH = 14 so if you are given one you can easily solve for the other. If you are given the concentration of H+ or OH- instead you can use take the negative log in order to obtain the pH or pOH instead.
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Re: pH v.pOH
Hi!
pOH and pH are related because the sum of pOH (= -log[OH-] ) and pH (= -log[H+]) is equal to 14. They are also related because you can add the 10^-pH or 10^-pOH to get Kw=10^-14, which can give the relative concentrations of [H+] and [OH-].
I hope this helps!
pOH and pH are related because the sum of pOH (= -log[OH-] ) and pH (= -log[H+]) is equal to 14. They are also related because you can add the 10^-pH or 10^-pOH to get Kw=10^-14, which can give the relative concentrations of [H+] and [OH-].
I hope this helps!
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Re: pH v.pOH
Hi! As some background, pH + pOH = 14. The highest pH that can be attained is 14. If you are trying to find the pOH when given the pH, you just subtract from 14. This goes the same for if you are given pOH and are trying to find the pH. If you are given the [H+] or [OH-] concentration, you plug the corresponding concentration into these equations: pH=-log[H+] or pOH=-log[OH-]. Once you have your pH or pOH value, you subtract it from 14 to find what you are looking for (pH or pOH). I hope that helped!
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Re: pH v.pOH
pH and pOH are inversely related. As pH goes up, pOH goes down and vice versa. pH+pOH=14 is the most direct equation but since pH is just the -log[H+] and pOH is just the -log[OH-] you can also use the equation [H+][OH-]=10^-14.
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Re: pH v.pOH
The sum of pH and pOH is 14. While pH is the measure of [H+], pOH is the measure of [OH-]. As long as you have one of the molarities or pOH/pH, you should be able to calculate the rest.
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Re: pH v.pOH
The sum of pH and pOH is equal to 14, meaning they are inversely related. If you are able to calculate the pH or the pH of a molecule you can determine the other via simple subtraction.
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Re: pH v.pOH
pH + pOH = 14, so if given pH, you can subtract the value of pH from 14 to find pOH and vice versa.
Re: pH v.pOH
The pH and pOH are inversely related and they are equal to 14. The way to figure out pH if given pOH is to subtract pOH from 14.
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Re: pH v.pOH
Hello!
pH and pOH are inversely related and pH + pOH = 14. Also you can find the pH when you take the -log of [H3O+] ion concentration and you can find the pOH when you take the -log of [OH-] ion concentration.
pH and pOH are inversely related and pH + pOH = 14. Also you can find the pH when you take the -log of [H3O+] ion concentration and you can find the pOH when you take the -log of [OH-] ion concentration.
Re: pH v.pOH
To understand why the two are inversely proportional, remember that if you have a high concentration of hydronium atoms, you have an acidic solution. Therefore, you will have a low concentration of hydroxide.
Re: pH v.pOH
To understand why the two are inversely proportional, remember that if you have a high concentration of hydronium atoms, you have an acidic solution. Therefore, you will have a low concentration of hydroxide.
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Re: pH v.pOH
pH is a value that represents acidity of a substance based on the concentration of H+, whereas pOH represents how basic a substance is based on the concentration of OH-. However, in a substance, pH and pOH added together should always be equal to 14.
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Re: pH v.pOH
The key difference between pH and pOH is that pH is a measure of hydrogen ions whereas pOH is a measure of hydroxide ions.
pH = −log10 [H+]
pH = −log10 [OH–]
pH = −log10 [H+]
pH = −log10 [OH–]
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Re: pH v.pOH
There were about three or four questions about pH on the test, hopefully you felt confident enough answering them:)
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Re: pH v.pOH
Natalie Swerdlow 3K wrote:Calculating pH is done by taking the -log of the H3O+ concentration while the pOH is calculated by taking the -log of the OH- concentration. To find the other, subtract that number from 14. For example, if you solved for pOH, calculate 14-pOH to find pH.
I thought it was -log[H+]?
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Re: pH v.pOH
Their relationship is inversely proportional. If we look at the formula 14=pH + pOH, then we will notice that when pH increases pOH will decrease. They have a equilibrium point at 7 when ph=7 and pOH=7
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Re: pH v.pOH
pH + pOH = 14
When given pH, you can calculate pOH by subtracting the pH from 14.
14-pH = OH
14-pOH = pH
When given pH, you can calculate pOH by subtracting the pH from 14.
14-pH = OH
14-pOH = pH
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Re: pH v.pOH
pH and pOH are related because when added together, they sum up to 14. Thus if you have one, you can always find the other by subtracting the one you have from 14. Hope this helps!
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Re: pH v.pOH
You can think of it as pH being one side of the seesaw and pOH is the other- when pH is high, pOH is low and vice versa. To calculate it, you can just remember pOH + pH = 14, but it also helps to remember their relationship. This also helps with calculating [H+] and [OH-] concentrations.
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Re: pH v.pOH
pH and pOH are both used to express the acidity of a solution. pH = -log [H+] while pOH = -log{OH-]. When given either pH or pOH, you subtract whichever term is given by 14 to find the remaining term.
pOH + pH = 14.
pOH + pH = 14.
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Re: pH v.pOH
For calculating both pH or pOH, I use the following formulas:
pH = 14-pOH = -log[H+]
pOH = 14-pH = -log[OH-]
A key thing to remember is that these two concepts are inversely related, hope this helps goodluck!
pH = 14-pOH = -log[H+]
pOH = 14-pH = -log[OH-]
A key thing to remember is that these two concepts are inversely related, hope this helps goodluck!
Re: pH v.pOH
the values of pH and pOH should add up to 14, therefore you can find either pH or pOH by subtracting the given value from 14.
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Re: pH v.pOH
pH + pOH = 14. Therefore, to find pH subtract the pOH from 14, and to find the pOH subtract the pH from 14.
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Re: pH v.pOH
Remember that the values of pH and pOH added together equal to 14! Using that and the formulas Lavelle provided, these calculations are fairly simple. Say for example, a problem states that the pH of a solution is equal to 2.9 and it wants the pOH, all you have to do is subtract the pH value from 14, and there you have the pOH! (11.1 in this example I provided).
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Re: pH v.pOH
pH + pOH = 14. Therefore if you find pH or pOH, you can just put the value into the equation and solve for the other.
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Re: pH v.pOH
pH and pOH add up to 14. You can also use the relationship between the following equations to calculate differnt values: -log[H3O+]= pH, -log[OH-] = pOH, [H3O+]= 10^-pH, and [OH-]=10^-pOH.
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Re: pH v.pOH
pH+pOH=14 always. So as pH goes up, pOH goes down and vice versa. pH measures the concentration of H+ and pOH measures the concentration of OH-. Hope this helps!
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Re: pH v.pOH
Hello, pH plus pOH equals 14 therefore, if you are know one of the values, you can easily calculate the other.
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