pOH
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Re: pOH
What I did to answer this question was use the equation pOH= 14-pH and it gave me the correct answer. If you havent calculated the pH yet, you would need to use the equation pH=-log[H+]. Just plug it into the calculator and u should get the correct answer. I hope you understand!
Last edited by Anisa Morales 1L on Sun Dec 05, 2021 8:39 pm, edited 1 time in total.
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Re: pOH
To calculate the pOH given that [H+] is 2.9×10 ^−11 M, you would use the concentration of [H+], you use pH=-log[H+] or in this case pH=-log[2.9×10 ^−11] to solve for pH. Then you would do 14-pH= pOH
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Re: pOH
You would first use the [H+] given to find the pH (pH=-log[H+]. Then to find pOH use the equation pOH= 14-pH
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Re: pOH
Hello,
You would first find the pH using pH= -log[H+] and then once you you get this you can just do pOH= 14-pH.
Hope this helps.
You would first find the pH using pH= -log[H+] and then once you you get this you can just do pOH= 14-pH.
Hope this helps.
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- Posts: 100
- Joined: Fri Sep 24, 2021 6:47 am
Re: pOH
First you take the -log of the concentration of H+ to get the ph and then you do 14-ph to get POH.
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Re: pOH
First take the -log of the concentration of H+: 2.9x10^-11. This should equal 10.53. We know that pH+pOH=14, so plug in pH and we get 10.53+pOH=14. Therefore pOH equals 3.46. Hope this helped!
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Re: pOH
When given a H+ concentration and you want to calculate a pOH value, just find the pH and once you do that subtract it from 14 to get your pOH
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