pOH

[705596384]

How do we calculate the pOH of a h+ that is equal to 2.9×10 ^−11 M at 25 °C.

[Anisa Morales 1L]

What I did to answer this question was use the equation pOH= 14-pH and it gave me the correct answer. If you havent calculated the pH yet, you would need to use the equation pH=-log[H+]. Just plug it into the calculator and u should get the correct answer. I hope you understand!

[bernal_maria1A]

To calculate the pOH given that [H+] is 2.9×10 ^−11 M, you would use the concentration of [H+], you use pH=-log[H+] or in this case pH=-log[2.9×10 ^−11] to solve for pH. Then you would do 14-pH= pOH

[Madelyn_Rios_2c]

You would first use the [H+] given to find the pH (pH=-log[H+]. Then to find pOH use the equation pOH= 14-pH

[Mario Prado 1K]

Hello,

You would first find the pH using pH= -log[H+] and then once you you get this you can just do pOH= 14-pH.

Hope this helps.

[Nithya Narapa Reddy]

First you take the -log of the concentration of H+ to get the ph and then you do 14-ph to get POH.

[Hudson2J]

To find the pOH, we can first find the pH by taking the -log base 10 of the H+ concentration. This gives us a pH of 10.54. We then subtract that from 14 to get a pOH value of 3.46.

[Kailin Mimaki 2K]

First take the -log of the concentration of H+: 2.9x10^-11. This should equal 10.53. We know that pH+pOH=14, so plug in pH and we get 10.53+pOH=14. Therefore pOH equals 3.46. Hope this helped!

[Chris Korban 1D]

When given a H+ concentration and you want to calculate a pOH value, just find the pH and once you do that subtract it from 14 to get your pOH

[PatrickV]

Another way in addition to what others have said, is that you can use the formula 1X10^-14=[H+][OH-] to find the concentration of OH and then use -log[OH-]=pOH

[Yalit Gonzalez 1A]

First find the pH using -log([H+]). Then, subtract the pH from 14 to get the pOH