Achieve W2 #5
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Achieve W2 #5
Hi everyone! This is the question for reference:
I was able to get the correct answer, but I'm confused as to why [B]formal is used in this equation and why [B]formal is different from [B]?Re: Achieve W2 #5
Hi,
B is just used as a substitute for a base. It goes like this B + H2O <--> BH+ + OH-. I'm not sure if this answers your question, but I hope this helps.
B is just used as a substitute for a base. It goes like this B + H2O <--> BH+ + OH-. I'm not sure if this answers your question, but I hope this helps.
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- Posts: 129
- Joined: Fri Sep 24, 2021 5:52 am
Re: Achieve W2 #5
Hi all, I'm still a bit confused about my original question, so I thought rephrasing it might be better. In the problem, in order to find % protonation, we have to do [OH-]/([B]+[BH+]) x100%. However, I don't understand why we have to add [BH+] to [B] because [BH+] is part of the products. I'd appreciate any help on this, thanks!
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Re: Achieve W2 #5
We have to had [BH+] to [B] because we are looking for the % protonated which is where we have the hydrogen atom give another proton, in a sense, giving it a positive charge. Opposite to % ionization where we would just put the X we found/the initial value given of the reactant, in this question we are asked for the % protonated where we put [BH+]/[B]formal. [B]formal = [BH+]+[B] which is the X we found adding the initial value given of the reactant. [BH+] is actually the reactant in this case.
I hope that helped.
I hope that helped.
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- Posts: 129
- Joined: Fri Sep 24, 2021 5:52 am
Re: Achieve W2 #5
Shannon Lau 14B - 1H wrote:We have to had [BH+] to [B] because we are looking for the % protonated which is where we have the hydrogen atom give another proton, in a sense, giving it a positive charge. Opposite to % ionization where we would just put the X we found/the initial value given of the reactant, in this question we are asked for the % protonated where we put [BH+]/[B]formal. [B]formal = [BH+]+[B] which is the X we found adding the initial value given of the reactant. [BH+] is actually the reactant in this case.
I hope that helped.
Thanks! That does help me a lot. I have a clarifying question, do we always use [BH+], [B], and [OH-] when doing % protonation? Similarly, do we always do [HA], [H+], and [A-] when doing % ionization?
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