6D 15

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Natalie Vu 1I
Posts: 132
Joined: Fri Sep 24, 2021 6:02 am

6D 15

Postby Natalie Vu 1I » Sat Jan 22, 2022 12:31 am

I was wondering why the problem had AlCl3 in the initial problem but Al(H2O)6 in the solution?

Phillip Ma 1J
Posts: 100
Joined: Fri Sep 24, 2021 7:05 am

Re: 6D 15

Postby Phillip Ma 1J » Sat Jan 22, 2022 10:38 am

If you read the chapter, you will see that they give you the Ka value for Al(H2O)6 3+. This makes sense because once AlCl3 is dropped into water, it will dissociate and Al 3+ will form a complex with H2O (as we learned in Chem 14A).


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