Polyprotic acid vs base dissociation
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Polyprotic acid vs base dissociation
When H2SO4 dissociates do we assume that it loses both H+ at once or that it loses 1 H+ and then HSO4- later loses another H+. I'm asking because for the bases like BaOH2, it loses both OH- at the same time. How come H2SO4 only loses 1 H+ as a strong acid and then functions as a weak acid when it loses the second H+ but BaOH2 loses both OH- at once as a strong base?
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Re: Polyprotic acid vs base dissociation
I think that we treat the first dissociation as a strong acid, so it completely loses the first H+, but for the second dissociation we treat it as a weak acid and use an ICE table and the Ka to calculate the second H+, then add the two H+ concentrations from the two dissociations to get the total [H+]
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Re: Polyprotic acid vs base dissociation
H2SO4 is a special case because it can lose the first H+ and become HSO4- which is amphiprotic. In this case, you would assume that it is a strong acid when it dissociates to become H+ and HSO4-.
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