textbook 6D.5

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rita_h
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textbook 6D.5

Postby rita_h » Wed Jan 26, 2022 9:05 pm

Just to confirm- the calculation of percentage protonated = [the value of x we obtain from the ICE table (corresponding to concentration of OH-) / the initial concentration of the base]*100?
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Sunny Xiao 1A
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Re: textbook 6D.5

Postby Sunny Xiao 1A » Thu Jan 27, 2022 1:26 am

Yes, that's correct.
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Kayla Arellano 1K
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Re: textbook 6D.5

Postby Kayla Arellano 1K » Thu Jan 27, 2022 9:06 am

rita_h wrote:Just to confirm- the calculation of percentage protonated = [the value of x we obtain from the ICE table (corresponding to concentration of OH-) / the initial concentration of the base]*100?


Yes, and if we were working with acids it would be [conjugate base]/[acid]x100%
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