Sapling HW Q6

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Evonne Hsu 1J
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Joined: Wed Sep 30, 2020 9:35 pm

Sapling HW Q6

Postby Evonne Hsu 1J » Sun Jan 17, 2021 2:43 pm

Can someone please explain the step-by-step process of this question? Thank you!
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Stuti Pradhan 2J
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Re: Sapling HW Q6

Postby Stuti Pradhan 2J » Sun Jan 17, 2021 5:10 pm

For this question, it is important to know that the cation of a strong base and the anion of a strong acid create a neutral salt, the cation of a strong base and the anion of a weak acid create a basic salt, and the cation of a weak base and the anion of a strong acid create an acidic salt. HClO4, HBr, HI, HCl, HNO3, H2SO4, and HClO3 are all strong acids, so their anions will be spectator ions. LiOH, NaOH, KOH, Ca(OH)2, and Ba(OH)2 are a few examples of strong bases, so their cations will be spectator ions as well. Anions of weak acids, such as CN-, will attract the H+ from water and therefore result in a more basic solution. On the other hand, cations of weak acids, such as NH4+, will attract the OH- from water and be acidic.

Hope this helps!

Nane Onanyan 1G
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Re: Sapling HW Q6

Postby Nane Onanyan 1G » Sun Jan 17, 2021 5:13 pm

First write the bases and acids the salts are derived from.
For example NaF is derived from NaOH and HF.
A salt will be basic if it contains the conjugate base of a weak acid. In this case, HF is weak, so it’s conjugate base (F-) will be strong and therefore the salt is basic.
Same process for acidity just vice versa.

Quinton Sprague 1A
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Re: Sapling HW Q6

Postby Quinton Sprague 1A » Sun Jan 17, 2021 5:15 pm

To determine the answer you must know where the salts are derving. The acidity of the compounds they come from determine these properties of the subsequent salt.


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