Ph and Poh

[505764547JY]

From a given concentration, how does one find the poh?

[smrithi n]

If the H3O+ concentration is given, you can take the -log of this. If the OH- concentration is given, you can take the -log of this and subtract this value from 14.

[Alan Lee 2I]

It depends on what the question gives you, but typically from a pH you can just subtract that pH value from 14 to get a pOH. 14 - pH = pOH. If you have H3O+ concentration you use the -log() to find the pH and you can get pOH with the equation above. Same can be done if given a OH- concentration

[Jess Kosz 1B]

Depending on whether Oh- or H3O+ is given as a product or reactant, then you can find the concentration of such ion by using an ICE table and then solve for the pH by using -log[OH- or H3O] = pOH or pH!

[Angela Ke]

If you're given the concentration of OH-, the pOH is simply found by plugging the concentration into the equation: pOH = -log[OH-]. If you're given the H+ concentration, you'd need to first find the pH using the equation pH = -log[H+], then convert it to pOH using the equation pH + pOH = 14.
Furthermore, if you're given the concentration of an acid or base, you'd need to set up an ICE table.

[105897549]

Hi!
If the concentration of [OH] is given, then you can simply find the pOH by pOH= -log([OH]). If the concentration of the [H3O+] is given, then you can also do the same process by pH= -log([H3O+]).

[Julia Scheithauer 1J]

you can take 14-pH to get pOH. You can also take the -log of kb to find pOH.

[Min Hur 1L]

It depends on which concentration you are given. If you are given [H3O+] then you do -log[H3O+] then subtract the found number from 14 to get the pOH. If you are given [OH-] then you do -log[OH-] and that is your pOH.