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Postby Sebastian » Sun Nov 20, 2016 3:21 pm

Why is it that [H3O][OH-] always equals the constant 10^-14?

Serena Patel 2H
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Re: [H3O][OH-]=10^-14

Postby Serena Patel 2H » Sun Nov 20, 2016 3:30 pm

Because that will always equal the Kw or the ionization constant for water. From the equations of two water molecules in equilibrium with [H3O+] and [OH-], liquids are not written in the Kw, so only [H30+] and [OH-] will be in the equation making those two equal to the ionization constant (Kw).

Yesenia Munoz 1G
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Re: [H3O][OH-]=10^-14

Postby Yesenia Munoz 1G » Sat Nov 26, 2016 7:18 pm

The equilibrium constant for any reaction, is called the water dissociation constant which is Kw. Because every H+ (H3O+) ion that forms is accompanied by the formation of an OH- ion, the concentrations of these ions in pure water are the same and can be calculated from Kw. Therefore, Kw = [H3O+][OH-] = 1 × 10^-14

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