pH formula?

[Saleha_Mian_3E]

What is the pH formula? and do we need to know how it was derived?

[Sierra Cheslick 2B]

The pH formula is -log[H+]. I believe we would need to know how to derive it.

[305127455]

I don't think we need to know how to derive it since pH is just an invented representation of proton concentration. For acid it's (-log[H+]), for base it's 14 - (-log[OH-])

[Jonathan Cheng 3C]

pH = - log[H+] while pOH is either 14 - pH or -log[OH-]. We do not need to know how these formulas were derived.

[Henri_de_Guzman_3L]

We don't need to know how they're derived although reading through the textbook I feel it is helpful in understanding how they work.

[Krista Mercado 1B]

The pH formula is pH = -log[H+]. I don't think we need to know how it is derived.

[Lisa Werner 2F]

I think you also need to know that pH + pOH = 14.

[Karina Koo 2H]

@305127455 wait shouldnt pOH be 14-(-log[H+]) ?

[NRodgers_1C]

Don't forget that because pH= -log[H3O+]= -log(1.0x10-7) = -(-7)=7 for a change in 1 pH unit, the [H3O+] changes by a factor of 10.

[gferg21]

The acid and base concentrations of the formula add up to 14, so there may be a pH of 8, which means there is a pOH of of 6

[MBouwman_4A]

The formula for pH is -log[H+] and pOH is -log[OH-]. I don't think we need to know the derivation, but it is helpful to know that pH + pOH = 14

[Callum Guo 1H]

pH=-log[h+]

[preyasikumar_2L]

You just need to know how to calculate pH and pOH from the [H+] and [OH-] given, and vice versa. pH = -log([H+]) and pOH = -log([OH-]) = 14 - pH

[Mitchell Koss 4G]

No you do not need to understand how logarithms are derived

[Juana Abana 1G]

so is it fine to just know the pH formula?

[Claire Grover 3G]

The formula is -log[H+] but I'm not sure if we need to know how to derive that.

[chrischyu4a]

pH=-log[H3O+]

[Callum Guo 1H]

it's -log[h+] and i doubt we would need to derive it

[AveryAgosto]

-log[H+] and I think we just need to know that pH+pOH= 14

[Annie Ye]

pH= -log(H+) you can also find pH from the equation 14= pOH+ pH if you were given the pOH.

[Natalie C 1K]

the pH is calculated using the formula: pH= -log[H3O+]

[Leyna Dang 2H]

You could find pH using pH=-log[H+]. Or, if you have the pOH, you could subtract it from 14 to find the pH.

[Stacey Phan 2K]

You can use the formula pH = - log[H+]

[lwon Dis2I]

What is the difference between pH=-log[H3O+] and pH=-log[H+]?

[Sophia Spungin 2E]

Professor Lavelle mentioned that when you see 'p' in chemistry it means take the negative log. So 'pH' means to take the negative log of the species with H+, or H3O+

[Jasraj Parmar 3H]

The pH forumla is pH = - log [H3O+].

[Yeprem]

P itself just stands for -log
When you say pH it means calculating the -log [H3O+] where the brackets show the concentration of the H3O+ ion
pOH is -log[OH-]

[jasmineculilap_3F]

pH = -log[H+]. I don't think we need to how it was derived.

[Ava Nickman]

pH= -log[H+]
pH= 14-pOH
pH= 14 - (-log[OH-])

it depends on what you are given

[305614361]

The pH formula is pH = -log10[H+] and [H+] = 10^-pH

[Jack_Pearce_2H]

I don't think you need to know how it was derived but definitely know that ph=(-log([H+]) and that [H+]=10^(-pH)

[Ethan Goode 2H]

The formula is -log[H+], basically just measuring the amount of protons in a solution, determining if it is acidic or basic.

[Joshua Eidam 2A]

Just to clarify, when using the concentration of OH to find the pH, you simply subtract -log[OH-] from 14 and that will equal the pH?

[Joshua Eidam 2A]

What is the difference between pH=-log[H3O+] and pH=-log[H+]?

They are the same thing. The H3O+ just represents the H+ bonded with an H2O but the concentration of either of them can be used to find the pH.

[Joshua Eidam 2A]

Also, when trying to find the concentration of the H+ or OH- from a pH or pOH, how do you do the reverse of -log[ ]?

[Nick Saeedi 1I]

The pH formula is -log[H+].

[Ariel Guan 1H]

pH = -log[H+]
[H+] = 10^(-pH)
pOH = -log[OH-]
[OH-] = 10^(-pOH)
14 = pH + pOH

[DPatel_2L]

pH=-log[H+]

[Kaili Valenzuela 2B]

Hi! I think this would be helpful to know
pH=14.00-pOH= -log[H+]
pOH=14.00-pH= -log[OH-]

[Mingzi Yang 1E]

pH = -log[H+]
[H+] = 10^(-pH)
pOH = -log[OH-]
[OH-] = 10^(-pOH)
14 = pH + pOH

This is helpful! Thank you.

[Lorraine Jiang 2C]

Hi! The formula to calculate pH is -log[H+]

Hope it helps!

[Kayla Booker 1F]

pH formula is pH=-log[H+] and Im not sure if we need to know how it's derived, but another formula for pH is pH=14.00-pOH

[Sophia Kalanski 1A]

pH=-log[H+]
it's also helpful to note that pH+pOH=14 and that [H+][OH-]=1*10^-14

[Andy Hernandez]

The pH formula is -log[H+]

[805421690]

acid: (-log[H+]
base: 14 - (-log[OH-])

[Nicole Bruno Dis 1B]

The pH formula is -log[H+], and to derive it, you should know how to determine its relation to pKa and pOH.

[Sejal Parsi 3K]

pH= -log[H+] and you don’t need to know how to derive it.