6D11 E and F

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Jedrick Zablan 3L
Posts: 68
Joined: Sat Aug 17, 2019 12:17 am

6D11 E and F

Postby Jedrick Zablan 3L » Fri Dec 06, 2019 2:07 am

Hello! Can anyone help me with E and F on 6D11? How do I write the chemical equation for those? Thanks!

Decide whether an aqueous solution of each of the follow- ing salts has a pH equal to, greater than, or less than 7. If pH . 7 or pH , 7, write a chemical equation to justify your answer. (a) NH4Br; (b) Na2CO3; (c) KF; (d) KBr; (e) AlCl3; (f) Cu(NO3)2.

Ryan 1K
Posts: 75
Joined: Fri Aug 09, 2019 12:15 am

Re: 6D11 E and F

Postby Ryan 1K » Sat Dec 07, 2019 12:55 am

When the salts are in an aqueous solution, the cation and anion will react differently. In the case of AlCl3, the small, highly positive Al3+ cation will interact with the water molecules and will cause the water molecules to give up a proton, acting as an acid. The Cl- anion is the conjugate base of a strong acid, HCl, so we know that it will be a weak base. As such, the solution will have a pH < 7.

As for writing the chemical equations, the Cl- ions, since they don't react, will cancel out, leaving just the Al3+, which will react to water to form H3O+ ions.

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