Textbook 6B 1

[005493723]

Hi, I am confused at how to go about solving textbook problem 6B 1) The molar concentration of HCl in hydrochloric acid is reduced to 12% of its initial value by dilution. What is the difference in the pH values of the two solutions?

I feel like it is missing information and I know sometimes the textbook gives you problems where you need to just look up information in order to do it, but I am not quite sure what to know/look up. Could someone either tell me what I need to find first or just how they went about solving it?

[Alex Yeghikian 1C]

The diluted solution is 12% the strength of the original solution. In other words, the molarity of hydronium ions is 12% of the original solution. The pH scale is the -log([H₃O⁺]). Therefore, you would calculate -log(0.12) to receive a change in pH of 0.92.

[Allison Li 2F]

Because the new solution is reduced to 12% of its initial value, we can find the change in the pH. To find the pH, we do -log[H3O+]. Therefore, we can just do -log[0.12], which gives us 0.92.