Textbook 6B.5 c and e

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Tala Ayoub 1H
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Textbook 6B.5 c and e

Postby Tala Ayoub 1H » Wed Dec 01, 2021 9:36 pm

Hi I'm a bit confused on how to solve parts c and e of question 6B.5 and was wondering for when calculating the pOH we just take the negative log of the concentration like we do for the pH correct?
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Noah Ho 1F
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Re: Textbook 6B.5 c and e

Postby Noah Ho 1F » Wed Dec 01, 2021 10:08 pm

There are multiple ways to find pOH. You can either take the negative log of the OH- concentration or you can find the pH and subtract the pH from 14, giving you pOH.
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Jiane_Beach_1D
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Joined: Fri Sep 24, 2021 6:07 am

Re: Textbook 6B.5 c and e

Postby Jiane_Beach_1D » Fri Dec 03, 2021 9:36 pm

Yes, to calculate the pOH you can use the equation -log[OH-] or you can calculate subtract the pH from 14. Either way works, it just depends on what information you are given.
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