Ch.13 #105

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Michael Lonsway 3O
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Ch.13 #105

Postby Michael Lonsway 3O » Thu Dec 01, 2016 6:20 pm

I'm having trouble with part b) since I can't find the new H3O+ concentration. How would I calculate it?

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Re: Ch.13 #105

Postby Chem_Mod » Fri Dec 02, 2016 11:54 am

You are given the initial pH.

Now you must consider what will happen to the equilibrium of this system after the addition of H3O+. This means you will set up an ICE table where the initial concentration of H3O+ is now not zero, but 0.65 umol.

The resulting equilibrium concentration of H3O+ can be used to find the new pH.

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