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HW 13.13

Posted: Fri Dec 02, 2016 2:38 pm
by yasminea 3L
The pH of 0.40 m HF(aq) is 1.93. Calculate the change in pH when 0.356 g of sodium uoride is added to 50.0 mL of the solution. Ignore any change in volume.

Re: HW 13.13

Posted: Fri Dec 02, 2016 4:12 pm
by Simon Kapler 3I
Just set up an ICE table with 0.40 as the initial concentration of HF, and find out the concentration of F- (coming from NaF) by dividing the moles of F- coming from the amount of NaF you're given by the volume of the solution. Then, just plug it into the ICE table and solve for x.