Textbook 6B.5

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Alison Le 2E
Posts: 50
Joined: Fri Sep 24, 2021 6:45 am

Textbook 6B.5

Postby Alison Le 2E » Sun Dec 05, 2021 3:03 am

Hi! I was wondering how to solve c of this problem:
Calculate the pH and pOH of each of the following aqueous solutions of a strong acid or base
c) 0.0092M Ba(OH)2

Thanks!

Natalie Swerdlow 3K
Posts: 101
Joined: Fri Sep 24, 2021 7:12 am
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Re: Textbook 6B.5

Postby Natalie Swerdlow 3K » Sun Dec 05, 2021 8:38 am

First, you have to multiply the molarity by 2 because there are 2 OH present in the molecule. After that, you will calculate the pOH first by taking the -log(2*0.0092) since you are calculating the concentration of OH-. Once you have the pOH, you subtract that value from 14 to get the pH.


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