### 13.23 How to find final pH?

Posted:

**Wed Nov 30, 2016 6:00 pm**5mL 0.010M NaOH (aq) is titrated with 0.005M HCl (aq)

What is the pH of the final solution?

I don't understand how the answer key got that the final pH is 2.54, when 30.0 mL of HCl was added. Besides for trial-and-error, I don't really see a way to solve for the final pH. I understand that the pH at stoichiometric point in this case is 7, since the titration is between a strong acid and strong base. But in terms of the final pH, I don't know how to calculate this when the amount of titrant was not given.

What is the pH of the final solution?

I don't understand how the answer key got that the final pH is 2.54, when 30.0 mL of HCl was added. Besides for trial-and-error, I don't really see a way to solve for the final pH. I understand that the pH at stoichiometric point in this case is 7, since the titration is between a strong acid and strong base. But in terms of the final pH, I don't know how to calculate this when the amount of titrant was not given.