Stoichiometric Point Ca(OH)2 and HCOOH

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Kyle Sheu 1C
Posts: 87
Joined: Fri Jun 23, 2017 11:39 am

Stoichiometric Point Ca(OH)2 and HCOOH

Postby Kyle Sheu 1C » Mon Jul 31, 2017 8:32 pm

During the review session today, we did an example where we added a certain volume of NaOH to a aqueous HCOOH such that moles NaOH=moles HCOOH.

If we were to use Ca(OH)2, would we simply add half the volume to reach the stoichiometric point?

If so, then how would that fit our definition of the stoichiometric point "moles acid=moles base?"

Wu Yuchen A1
Posts: 24
Joined: Thu Jun 29, 2017 3:00 am

Re: Stoichiometric Point Ca(OH)2 and HCOOH

Postby Wu Yuchen A1 » Mon Jul 31, 2017 10:10 pm

Before answer we never use Ca(OH)2 as a titration base since it isn't strong base at all.
Your summary is correct. At this situation the mole of hydronium ion = mole of hydroxyl ion (if both the acid and base are strong)

Kyle Sheu 1C
Posts: 87
Joined: Fri Jun 23, 2017 11:39 am

Re: Stoichiometric Point Ca(OH)2 and HCOOH

Postby Kyle Sheu 1C » Mon Jul 31, 2017 11:29 pm

Thanks! A small question though: isn't calcium hydroxide a strong base? From what I remember, it's not very soluble, but it does ionize ~100%….please let me know!


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