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Stoichiometric Point Ca(OH)2 and HCOOH

Posted: Mon Jul 31, 2017 8:32 pm
by Kyle Sheu 1C
During the review session today, we did an example where we added a certain volume of NaOH to a aqueous HCOOH such that moles NaOH=moles HCOOH.

If we were to use Ca(OH)2, would we simply add half the volume to reach the stoichiometric point?

If so, then how would that fit our definition of the stoichiometric point "moles acid=moles base?"

Re: Stoichiometric Point Ca(OH)2 and HCOOH

Posted: Mon Jul 31, 2017 10:10 pm
by Wu Yuchen A1
Before answer we never use Ca(OH)2 as a titration base since it isn't strong base at all.
Your summary is correct. At this situation the mole of hydronium ion = mole of hydroxyl ion (if both the acid and base are strong)

Re: Stoichiometric Point Ca(OH)2 and HCOOH

Posted: Mon Jul 31, 2017 11:29 pm
by Kyle Sheu 1C
Thanks! A small question though: isn't calcium hydroxide a strong base? From what I remember, it's not very soluble, but it does ionize ~100%….please let me know!